I got Error using vertcat Dimensions of arrays being concatenated are not consistent. Error in Code_tubes (line 22) C = [q(1); q(2); q(3);

I try to do compitational kinematic analysis, but when i write the driving constrain, this error occur, i dont have any idea about whats wrong in my line. Please somebody help me

%Input

d = 27.5; %cm

l2 = 31; %cm

l3 = 37; %cm

l4 = 38.5; %cm

w2 = 2; %rad/s

teta2_o = pi/2; %rad

t = 0:0.001:2;

Numdata = size(t,2);

%Matrix coordinate

q = zeros(12,1);

q_all = zeros(12,Numdata);

qdot_all = zeros(12,Numdata);

qdot2_all = zeros(12,Numdata);

uC = zeros(2,1);

rC_all = zeros(2,Numdata);

for j = 1:Numdata

for i = 1:3 %number of iteration

%Constrain matrix

C = [q(1); q(2); q(3);

q(4) - (l2*cos(q(6)))/2;

q(5) - (l2*sin(q(6)))/2;

q(4) + (l2*cos(q(6)))/2 - q(7) + (l3*cos(q(9)))/2;

q(5) + (l2*sin(q(6)))/2 - q(8) + (l3*sin(q(9)))/2;

q(7) - q(10) + (l4*cos(q(12)))/2;

q(8) - q(11) + (l4*sin(q(12)))/2;

q(10) + (l4*cos(q(12)))/2 - d;

q(11) + (l4*sin(q(12)))/2;

q(6) - teta2_o - w2*t];

Answer 1

[Joseph Cheng]

a quick scan shows it at the last row of C with

                q(6) - teta2_o - w2*t];

where everything up to that looks to be a 1x1 large as you're indexing through q for 1 index but then you have t which is defined as

                t = 0:0.001:2;

so you cant squeeze something that wide into a single index array entry.

Also it doesn't look like you're doing anything using the i and j for the for loop but that is another question

[Fauzanul Ardhi]

thanks a lot, it works, so i supposed to use t(j), intsead of t. tho i still have error in other line, hope i will figure it out somehow