# Transfer and write three lines into python: help

1 view (last 30 days)
Mark Sc on 14 Oct 2021
Answered: Yongjian Feng on 23 Oct 2021
Hi all,
Please anyone help me in writing the following lines in python:
clear all;
clc;
x=[5,31,41,51,61]
y=[1,11,21,31,5;4,14,24,34,5;
7,17,27,37,5;34,44,54,64,5;37,47,57,67,5]
for i length(x):-1:1
if (sum(y==x(i),'all')<.1)
x=x-(x>y(i))
end
end
in python:
import numpy as np
x=np.array([5,31,41,51,61])
y=np.array([[1,11,21,31,5],[4,14,24,34,5],
[7,17,27,37,5],[34,44,54,64,5],[37,47,57,67,5]])
for i in range(len(x)-1,2,-2):
if (np.sum(y==x[i],'all')<.1):
x=x-(x>y[i])
Rik on 15 Oct 2021
This is a Matlab forum, so this isn't the right place to ask for help with python.
I don't see why the code you wrote wouldn't do what you expect. The only thing I notice is that you have the number 2 as argument to the range function, while in Matlab your step size is 1. Are you sure that is correct?

Yongjian Feng on 23 Oct 2021
1. The numpy.sum doesn't take 'all'
2. The for loop needs to be adjusted to 0-base
import numpy as np
x=np.array([5,31,41,51,61])
y=np.array([[1,11,21,31,5],[4,14,24,34,5],
[7,17,27,37,5],[34,44,54,64,5],[37,47,57,67,5]])
for i in range(len(x)-1,0,-1):
if (np.sum(y==x[i])<.1):
x=x-(x>y[i])
print(x);