how to convert decimal values into 8bit binary sequence and represent in a 256*256 matrix

hello

I have used the following code to represent decimal values in a matrix to 8bit binary sequences in place of each value. but im not able to get the 8 bit value...instead i get only one bit answer. also in case an 8bit sequence is obtained how should i represent each sequence separately? please help.

>>clc
>>clear all
>>close all
>>a=imread('C:\Users\Abzz\Desktop\lena.png');
>>imshow(a)
>>disp(a)
>>for i=1:1:256
>>for j=1:1:256
>>b(i,j,:)=dec2bin(a(i,j),8);
>>end
>>end
>>disp(b)

thanks in advance

Answer 1

[Salaheddin Hosseinzadeh]

Hi Abirami,

You are aware that you're making a 256 x 256 x 8 matrix(3D matrix), and that's how it showed on MALTAB when you have a 3D matrix.

A quick solution would be to store it in a cell, so change your code as such

b{i,j,1} = dec2bin(a(i,j),8);

Hope that helps. Good Luck.

[Abirami]

thank u so much....it worked...i got exactly what i wanted...

[c kdg]

How to copy the above output binary sequence to a text file from command window Please reply.

[Stephen23]

@c kdg: pick an appropriate data export function:

https://www.mathworks.com/help/matlab/text-files.html

Answer 2

[Azzi Abdelmalek]

a=imread('C:\Users\Abzz\Desktop\lena.png');  
b=cell2mat(arrayfun(@(x) reshape(dec2bin(x,8)-'0',1,1,8),a,'un',0));