Display results in one matrix (nested for loops

Hello,

I am working on my final year project, a script that detects moods/emotions generated by audio files. I am currently stuck here:

for i=1:2

for j=4:10

    for k=2:3

      for l=1:2

        for m=1:2

X=(i,j,k,l,m);

End, end, etc.

The reason for this is that each element i,j,k,l,m of the array has several values (i.e. i is 1 or 2, j is 4 through 10 etc.)

Now the problem: I get each possible array in a single line, is there any way to store all of them in a single matrix?

Thank you in advance!

M.

[Salaheddin Hosseinzadeh]

I guess it's

X(i,j,k,l,m)=someting

it won't be a bad idea to correct your code.

You said you want it all in one matrix! Well, they are in one matrix as far as I understand! X is a matrix and apparently that's where you wanna save different values!

Your question is vague!

[Mihnea]

No, because of the for loop, it displays each value in the same vector with 5 elements and it prints it out for every iteration of the loop. I am looking to collect these iterations in one big 5 by n matrix.

Sorry if I'm being vague, I'm trying to work on a train full of people...

Answer 1

[Mischa Kim]

Mihnea, you probably want

 X(i,j,k,l,m) = ...

For large matrices you might want to pre-allocate memory:

 X = zeros(2,10,3,2,2);

[Mihnea]

Hmm, it doesn't seem to work, says dimension mismatch. Any other ideas?

[Mischa Kim]

What exactly are you assigning to X? E.g., you could do (as an example)

 X(i,j,k,l,m) = 10000*i + 1000*j + 100*k + 10*l + m;

What definitely does not work is something like you've shown

 X(i,j,k,l,m) = (i,j,k,l,m);

[Mihnea]

I am trying to assign possible values of each variable to columns 1 to 5.

For example:

X = [1 4 2 1 1]

    [1 4 2 1 2]

    [1 4 2 2 1]

    etc.

It bassically cycles through each variable value possible.

It does that nicely but it outpuuts one matrix with 5 columns at a time, I need it all in one big matrix.

[Mischa Kim]

I see. What you want is something like

 pp = 1;
 for i=1:2 
     for j=4:10
         for k=2:3
             for l=1:2
                 for m=1:2
                     X(pp,1:5) = [i j k l m];
                     pp = pp + 1;
                 end
             end
         end
     end
 end

[Mihnea]

Brilliant, thank you so much!

M.

[Vasilis Mitropoulos]

Thanks Mischa Kim, so simply and beautifully resolved what I wanted:)

Have a beautiful day!!!!!!!!!