solve matlab equation( 512*512*lo​g2(B))/2>=​=520000

sir i am new to this matlab i want to satisfy the equation (512*512*log2(B))/>=520000 by keeping what value of B this equation will be satisfied answer is 16 .. i want how to do code for this equation in matlab by taking B values automatically to satisfy this equation

Answer 1

[A Jenkins]

syms B
sym_b=solve(512*512*log2(B)/2==520000)
vpa(sym_b)

ans =

15.641263534925078400119749631703

[vaka sindhu]

sir i have to satisfy this equation by choosing which value of B will satisfy the equation

[Walter Roberson]

The answer is 15.641263534925078400119749631703 approximately, and "A Jenkins" shows one way it can be calculated.

[vaka sindhu]

sir i am getting error like this ?? Error using ==> mupadmex Error in MuPAD command: cannot differentiate equation [numeric::fsolve]

Error in ==> sym.sym>sym.mupadmexnout at 2018 out = mupadmex(fcn,args{:});

Error in ==> solve at 76 [symvars,R] = mupadmexnout('symobj::solvefull',eqns,vars);

Error in ==> Untitled7 at 2 sym_b=solve('(512*512*log2(B))/2==520000'); can u say me how to solve asap

[vaka sindhu]

sir i am getting can say me the code .....

[A Jenkins]

In older versions of MATLAB, you can try rearranging:

sym_b=solve((512*512*log2(B))/2-520000)

Answer 2

[Star Strider]

The easiest way is to take the base-2 antilog of both sides. You get the answer directly:

B = 2^(2*520000/(512^2))

gives:

B =

      15.6413e+000

[A Jenkins]

That was going to be my next proposal too, but then we are just teaching math, and not "code for this equation in matlab by taking B values automatically to satisfy this equation".