Clear all fields of a struct

Hi,

I have a struct with a number of fields that I want populate, and then store, each iteration through a loop. I want the struct to be empty and available each iteration. Is there a function to clear all the fields? Or do I just declare the whole thing again?

I tried setting each feild individually to [], like

myStruct.a = [];
myStruct.b = [];

But it's actually faster to declare the whole thing new each iteration, as in:

myStruct = struct('a', [], 'b', []);

Or maybe there's a better approach all together?

Cheers, Karl

Answer 1

[Karl]

A colleague suggested this:

myStruct = structfun(@(x) [], myStruct, 'UniformOutput', false);

It's about the same speed-wise, maybe a little faster on average. But it's nice and neat :)

[Azzi Abdelmalek]

clearing your variable doesn't make your code faster, maybe you need to pre-allocate

myStruct = structfun(@(x) zeros(1,100), myStruct, 'UniformOutput', false);

Answer 2

[Azzi Abdelmalek]

%example
a.b=1
a.c=2
a.d=3
%----------------
f=fields(a)
for k=1:numel(f)
  a.(f{k})=[];
end

[Karl]

Thanks for the reply. This approach does work, but it takes more or less the same amount of time as re-declaring the structure.

Surely there's a better way than resortimg to loops?