how to get index position of rows

i have a 2 matrix, matrix1 with dimension 2100*128 and matrix2 with dimension 16*128... i wanted to get the index positions of those rows which matches with matrix1, i did as below

 for v = 1:k
    inds = find(dbfea(1:2100,1:128)==tempfea(v,1:128));
    neighindex(v,1) = inds(1);
 end

but i'm getting error as

 ??? Error using ==> eq
 Matrix dimensions must agree.

 Error in ==> MainGUI>Retrieval_pushbutton_Callback at 304
    inds = find(dbfea(1:2100,1:128)==tempfea(v,1:128));

 Error in ==> gui_mainfcn at 96
        feval(varargin{:});

 Error in ==> MainGUI at 42
    gui_mainfcn(gui_State, varargin{:});

 Error in ==>
 @(hObject,eventdata)MainGUI('Retrieval_pushbutton_Callback',hObject,eventdata,guidata(hObject))

 ??? Error while evaluating uicontrol Callback

what should i do to rectify it....

[Walter Roberson]

You want to match rows against corresponding rows? Or you want to check if a row is found in any of the rows in the other matrix?

[Elysi Cochin]

i want to check if a row is found in any of the rows in the other matrix

sir but what is the difference between the 2 questions you asked....

Answer 1

[Andrei Bobrov]

[l0,idx] = ismember(tempfea,dbfea,'rows');
 out = idx(l0);