MATLAB Answers

Partition a Big Matrix Into Pieces According to Values from A Vector

22 views (last 30 days)
Alessandro
Alessandro on 4 Mar 2014
Commented: Alessandro on 4 Mar 2014
I have a big matrix (approx 2000x2000 size). Based on another boolean vector (which is 2000x1), i want to remove rows or columns from a copy of the original big matrix, wether the i-th element of the vector is equal to 0 or not. By using the following code:
if true
A = rand(2000); % Generate Random Matrix
b = zeros(2000,1); % Initialize Vector
for l=1:size(b,1)
c = rand(1);
if c>0.5;
b(l,1) = 1; % Just Putting Random 1's in the Vector
end
row_id = find(Boun); % Create a Vector Containing the Indices of Rows/Columns to Eliminate
A_copy = A; % Copy of the Original Matrix
counter = 0; % Create a Counter
for m=1:size(row_id,1);
A_copy(row_id(m)-counter,:) = []; % Eliminate row
A_copy(:,row_id(m)-counter,:) = []; % Eliminate column
counter = counter +1
end
end
The efficiency of the method is very poor. I know that messing around with matrices dimensions is not a good idea. Any suggestions?
Thanks in advance.

  0 Comments

Sign in to comment.

Accepted Answer

the cyclist
the cyclist on 4 Mar 2014
Instead of the for loop, you can do
A_copy(row_id,:) = []; % Eliminate rows
A_copy(:,row_id) = []; % Eliminate columns

More Answers (0)