Code bug with image algorithm

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mona
mona on 16 Jan 2014
Commented: Walter Roberson on 17 Jan 2014
Hello there,
Here's a part of the code that I'm using to approximate an image and I'm kind of not understanding the problem with the last line. I'm suspecting there's something wrong with the datatype of m. The value of m is (sqrt(M)-1)/2 where M is the number of coefficients.
sizeImage = size(riceImage,1);
A = zeros(sizeImage);
sel = (sizeImage/2-m:sizeImage/2+sizeImage)+1;
A(sel,sel) = B(sel,sel);
  1 Comment
José-Luis
José-Luis on 16 Jan 2014
It would be helpful if you posted the error you get.

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Answers (1)

Image Analyst
Image Analyst on 16 Jan 2014
Try this:
sizeImage = size(riceImage, 1); % Number of rows only (not # columns)
A = zeros(sizeImage); % rows by rows square image.
halfWidth = int32(sizeImage/2); % Round to nearest integer.
% The remaining code will go out of bounds and is nonsense.
% At least I don't understand the intent of it.
sel = (halfWidth -m : halfWidth + sizeImage)+1; % Maybe try end instead of sizeImage
A(sel,sel) = B(sel,sel); % No idea what this is supposed to do.
  1 Comment
Walter Roberson
Walter Roberson on 17 Jan 2014
sizeImage/2+sizeImage is going to be greater than sizeImage so you are attempting to index outside the "A" that you defined.

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