how to perform matrix manipulation for a game of battle ship?

sorry the question is a bit abstract .i am making a battleship game.on a 10x10 matrix.the user has to type in coordinate in (alphabets,number) style. i tried doing this for one ship and the matrix has gone all over the place and i am lost. what i did was
% code
Board=zeros(10);
A=1;
B=2;
C=3;
D=4;
E=5;
F=6;
G=7;
H=8;
I=9;
J=10;
%destroyer
ALPHArange='A':'J';
Drow= ALPHArange(randi(numel(ALPHArange))); %picks a random row for destroyer
Dcol=randi(100,1,1); %picks a random column for destroyer
Board(Drow,Dcol:Dcol+1)=2
here i want to place a ship called destroyer of unit length 2.(on the matrix two zeros ,beside each other,should become 2).....upon running the script i got an extremely lage matrix which made no sense

 Accepted Answer

roshan try this:
Board = zeros(10);
ALPHArange = 'A':'J';
Drow = ALPHArange(randi(numel(ALPHArange)));
Dcol = randi(9,1,1);
idx = find(ismember(ALPHArange, Drow));
Board(idx, Dcol:Dcol + 1) = 2;

3 Comments

perfect! that did the job...i will try using the same method for the other ship of different unit length! thankyou!
could u please explain the last two code lines please,i mean ,what do they mean?the help in the matlab is not clear.
idx = find(ismember(ALPHArange, Drow));
this line find the index of Drow in array ALPHArange. For example, if randomly choosen alphabet is 'E' then idx will have value 5, for 'C' value 3 and so on and it will be your row number in the next line
Board(idx, Dcol:Dcol + 1) = 2;
but when i tried this,the value of .......idx = find(ismember(ALPHArange, Drow))........... is always 1,even when the randomly choosen alphabet is 'E' or 'F'........ so, all the points i try to put into matrix always ends up in the first row.

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