i am supposed to get ecg signal from the ecg text data however the code should be written following the protocol i am new in matlab so a little help please..

 1. read the start bytes: 0x5A and 0xA5
 2. As soon you detect this, read the all 17 bytes
 3. Double check of these best just only have 0x5A, 0xA5 once. If there 
 is more you will need to discard the first 0x5A, 0xA5 as your starting 
 point and go back to step 1. If only once detected go to next step.
 4. Read byte 5th and 6th for Ch1. Combine this two bytes: 5th byte for 
 the high byte and 6th byte for the low byte and convert it to decimal.
 5. start the plot figure value versus time. X axes for the time; Y axes 
 for the value of that byte.
 6. Repeat this until the whole data finish.

the data is

E0 06 14 02 7A 02 62 7A FE A5 5A 02 02 02 17 00 
24 00 9D 00 21 00 0F 00 0C 0F A5 5A 02 03 01 F6 
00 07 00 9C 00 21 00 0F 00 0C 0F A5 5A 02 04 01 
E7 03 E9 00 9D 00 21 00 0F 00 0C 0F A5 5A 02 05 
02 0C 03 FF 00 9D 00 21 00 0F 00 0C 0F A5 5A 02 
06 02 22 01 9B 00 9D 00 21 00 0F 00 0C 0F A5 5A 
02 07 02 19 00 2D 00 9D 00 21 00 0F 00 0C 0F A5 
5A 02 08 01 F9 00 05 00 9D 00 21 00 0F 00 0C 0F 
A5 5A 02 09 01 E6 03 97 00 9D 00 21 00 0F 00 0C 
0F A5 5A 02 0A 02 06 03 FF 00 9D 00 21 00 0F 00 
0C 0F A5 5A 02 0B 02 21 02 38 00 9D 00 21 00 0F 
00 0C 0F A5 5A 02 0C 02 1D 00 3E 00 9D 00 21 00 
0F 00 0C 0F A5 5A 02 0D 01 FF 00 07 00 9D 00 21 
00 0F 00 0C 0F A5 5A 02 0E 01 E6 03 4B 00 9D 00 
21 00 0F 00 0C 0F A5 5A 02 0F 02 00 03 FF 00 9D 
00 21 00 0F 00 0C 0F A5 5A 02 10 02 1F 02 FC 00 
9D 00 22 00 0F 00 0C 0F A5 5A 02 11 02 1F 00 53 
00 9D 00 21 00 0F 00 0C 0F A5 5A 02 12 02 04 00 
09 00 9D 00 21 00 0F 00 0C 0F A5 5A 02 13 01 E5 
02 CB 00 9D 00 22 00 0F 00 0C 0F A5 5A 02 14 01 
FA 03 FF 00 9D 00 22 00 0F 00 0C 0F A5 5A 02 15 
02 1C 03 BC 00 9D 00 22 00 0F 00 0C 0F A5 5A 02 
16 02 20 00 68 00 9D 00 21 00 0F 00 0C 0F A5 5A 
02 17 02 09 00 0C 00 9D 00 21 00 0F 00 0C 0F A5 
5A 02 18 01 E8 02 18 00 9D 00 22 00 0F 00 0C 0F 
A5 5A 02 19 01 F5 03 FF 00 9D 00 22 00 0F 00 0C 
0F A5 5A 02 1A 02 19 03 FF 00 9D 00 22 00 0F 00 
0C 0F A5 5A 02 1B 02 22 00 94 00 9D 00 22 00 0F 
00 0C 0F A5 5A 02 1C 02 0E 00 10 00 9D 00 22 00

[Walter Roberson]

You still did not include a question.

That code will not work as it goes line-by-line but nothing in the protocol you described is line-oriented.

[Prabhav]

the question is the protocol however there is 256 data in 1 second..

Answer 1

[Walter Roberson]

http://www.mathworks.com/matlabcentral/answers/8026-best-way-s-to-master-matlab

In particular look at "for" and "==" and hex2dec() and fprintf()

[Prabhav]

I have tried for3 days to get syntax to do just this

like for data= start to end

scand data

if data have a5 5a then

scan 17 byte

if data don't have a5 5a then search 5th and 6th data and display

and yet I have not come up with a running program!!

[Walter Roberson]

You will find it easier to read all the data at the same time, and convert it to numeric, and do the searching in the resulting vector.

fid = fopen('YourFile.txt');
datacell = textscan(fid, '%x');
fclose(fid);
data_vector = datacell{1}(:);

[Prabhav]

'FF'

'A5'

'5A'

'02'

'01'

'00'

'00'

'03'

'FF'

'00'

'39'

'00'

'37'

'00'

'36'

'00'

'36'

'0F'

the output is this however I now need to display the combined value of 3rd and 4th data after searching the A5 5A and I am struggling with the search loop in the file. I really appreciate your help.

is anything can be done to group two datas A5 5A in a single cell using the syntax to make A55A data_vector=datacell{1} (:);

[Walter Roberson]

The output would be in decimal, not in hex. The '%x' format that I indicated for the textscan() means to convert hex to decimal. Please recheck what is stored in data_vector . With the data you listed, I would expect the first value to be decimal 240 (E0)

[Prabhav]

There is an error with the execution of the code. i've attached the text file with it thank you..

[Image Analyst]

I gave you an answer that works in your duplicate question: http://www.mathworks.com/matlabcentral/answers/104548#answer_113989

[Prabhav]

I am sorry but it didn't worked and i've pointed the error..