Output of every loop calculation to be used as vector.

Dear Friends,

I want an output element of every loop calculation, which can be used as a separate vector. Following is an example:

Suppose, after very loop(if-else or for) calculation, gives the value of some variable, say x. After coming out of loop, I want to use all the calculated values of x, as a separate vector, say y, so that the vector y will be

y=[1st value of x in 1st loop 2nd value of x in 2nd loop & so on...];

Can any of you please help me to get such output???...

Answer 1

[Sean de Wolski]

y = zeros(n,1);
for ii = 1:n
 y(ii) = some_value_of_x(possibly(ii))
end

[Timo Baumann]

Does this also work for nested for loops? Can't really get it to work unfortunatelly :/

[Stephen23]

"Does this also work for nested for loops?"

Of course:

y = zeros(m,n);
for ii = 1:m
    for jj = 1:n
        y(ii,jj) = yourScalarValue;
    end
end

[Timo Baumann]

Thank you for your quick response :)

[Timo Baumann]

ok sry to bother you again here, but I think I didn't get it right.

I'd like to store the vectors of cs, wsmax, thetas and Wnutz in seperate vectors, that I can call independetly later in the code.

wsmin = 2*pi*nsmin;

for eS = 0.4:0.1:eSg

for ds = 0.3:0.1:dsg

for hs = 0.01:0.01:hsg

cs = sqrt(1-eS);

wsmax = wsmin/cs;

thetas = 2*pi*rhos*hs*0.25*(ds/2)^2;

Wnutz = 0.5*thetas*(wsmax^2-wsmin^2);

end

end

end

Could you please help me with that?

[Stephen23]

"Could you please help me with that?"

LIke the examples on this page show, you should loop over indices, not data values.

"I'd like to store the vectors of cs, wsmax, thetas and Wnutz in seperate vectors"

You could use a cell array for that, although I strongly recommend putting indentically-sized numeric data into one numeric array rather than storing it as separate vectors.

[Timo Baumann]

Ok thanks :)

The reason I'd like to store everything in seperate vectors is that I'd like to display every variable depending of another one as I want in order to see the influence of each variable individually.

Thanks again for your help.