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Antonio Ribeiro


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Answered
Regularized Hypergeometric Function and Hypergeometric Function Syntax
I think you don't need this answer anymore but in order to clarify future queries about this, one could check the hypergeometric...

11 years ago | 3

| accepted

Question


why do I get an error with fsolve in R2012b if in R2007a it works fine ?
I'm facing with different results returned by the algorithm fsolve between the releases R2007a and R2012b. In my case, when I ru...

11 years ago | 1 answer | 0

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