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Question
多変数関数の条件付き極致について
z=x*y*cos(x^2+y^2)という多変数関数が、x^2+y^2<(pi/2),x>0,y>0という条件がある時の極大値と極小値の値を表示させる方法がわかりません。
2 years ago | 1 answer | 0
