This problem is yummy! :-)
Simple & interesting.
The same as the surface area of a cylinder but without calculating the area of the bottom surface (circle) of the cylinder:
Having finished all 15 problem just to see what is the leading solution looks like. Then I realize smaller size doesn't mean the solution is better, often it is at the price of understand-ability.
Remember, in most cases, you write program for humans not for machines.
SA = ((2*pi*r*h)+(2*pi*(r^2)))-(pi*(r^2));
calculating surface area except the base area
I do not think this exercise is correct. As one should not put frosting below the cake, the area of the cake to put frost on is the area of the circle on top of it plus the area of the "bent" rectangle on its sides. Thus:
function SA = func_frosting2(r,h)
ARectangle = pi*r*h;
ACircle = pi*r^2;
SA = ARectangle + ACircle;
I think the current solution is misleading
simple and fun.
just tricky one.
Back to basics 10 - Max Float
Find last zero for each column
04 - Scalar Equations 1
What is Sum Of all elements of Matrix
How many Fibonacci numbers?
Calculate Inner Product
Verify Law of Large Numbers
Find MPG of Lightest Cars
Plot Damped Sinusoid
Find the Best Hotels
Find the treasures in MATLAB Central and discover how the community can help you!
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office