Given an input vector and position (which is zero based) output the value
x = [1 2; 4 5] pos = [0 1] value = 5
x = [1 2 3 4 5; 6 7 8 9 0] pos = [1 3] value = 9
Filter AC, pass DC
Back to basics 9 - Indexed References
Back to basics 12 - Input Arguments
Replace multiples of 5 with NaN
Divisible by 3
I told you not separate me, but you did :( - ACDC
Create cosine function out of sine
Upper Matrix in LU Decompositon
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