Problem 403. Einsteinium-253 decay

Created by Bruce Raine

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Radioactive Einsteinium-253 has a half-life of 1,768,608 seconds. Given 1000mg of Einsteinium-253 at t=0 days, how much is left after 50 days?

EX: >> decay(50)

184

HINT: find k, then decay(50)

Use: decay(t)=10^3*e^(k*t)

NB: make sure you round your answer up to the next highest integer.

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Last Solution submitted on Dec 24, 2025

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Alfonso Nieto-Castanon on 25 Feb 2012

guess you mean minutes instead of seconds?

Bruce Raine on 25 Feb 2012

Hi, no I do mean seconds if you are referring to the constant, 29,476.8

Bruce Raine on 25 Feb 2012

I have readjusted it now so it is the correct value.

Rick Rosson on 25 Feb 2012

I believe you are always rounding up to the next highest integer rather than rounding to the nearest integer. In other words, you are using the ceil() function, not the round() function.

Bruce Raine on 25 Feb 2012

Hi Rick, yes you are quite right. I have made the correction as above. Thanks for your valuable input.

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Problem 403. Einsteinium-253 decay

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Problem 403. Einsteinium-253 decay

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