Problem 3008. Carnot cycle

Created by Ritwik Rudra

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Carnot engine is considered the most efficient heat engine.When operated between two temperatures T1 and T2, the efficiency is given by: efficiency=1-T1/T2 where T1<=T2 and both are in kelvin. Given the temperatures in degree celsius, find the efficiency.

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Last solution submitted on Oct 19, 2019

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Philemon Chavrier on 12 Feb 2015

I think their is a problem with the test case 3.

Romain Dupouy on 12 Feb 2015

I guess you're right

Ritwik Rudra on 12 Feb 2015

T1 and T2 do not necessarily imply x(1) and x(2).the higher temp. is always in den.

Anupam Agarwal on 13 Feb 2015

I have used Max(x) and Min(x) ... then also the test case does not satisfy...

Sylvain on 13 Feb 2015

The problem is the isequal() without any tolerance...

James on 13 Feb 2015

The conversion between Kelvin and Celsius is 273.15, not 273.

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Solution 1524888

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2 Comments

J. S. Kowontan on 10 May 2018

Sigh...a little challenge with tolerance? :)

bainhome on 10 May 2018

haha~just finish it as fast as I can, didn't have time realizing how stupid this answer is. I saw your answer by the way, it just avoid the tolerance issue with avoiding obvious subtract, brilliant move!

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Problem 3008. Carnot cycle

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Problem 3008. Carnot cycle

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Last 200 Solutions

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