input -> matrix (n*m) with at least one element equal to NaN;
output -> matrix(p*m), the same matrix where we deleted the entire line containing NaN;
Additional test cases have been added.
you can use find function... easy
function y = removeNaN(x)
[n m] = size(x);
for i = 1 : n
maxx = max(isnan(x(i,:)));
if maxx ~= 1
y = (x(i,:))
What is Wrong With THis Code CAn SomeOne Tell ME
It looks like y will return only the last non-NaN row, instead of collecting all of them.
This solution doesn't necessarily work if there are any Inf elements in the matrix. Perhaps it would be best to add a test case where that is the case.
Make the vector [1 2 3 4 5 6 7 8 9 10]
DNA N-Gram Distribution
05 - Vector Equations 1
Compute Fibonacci Number
Back to basics - mean of corner elements of a matrix
Create a matrix X, where each column is a shifted copy of the vector v
Find the elements of a matrix according to a defined property.
A quadrant matrix
Remove from a 2-D matrix all the rows that contain at least one element less than or equal to 4
vectorization in N
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office