Problem 2592. LocateMembership | Membership of Matrix in another matrix

Vishal

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Let a and b be given by

 a = [ 2 1 1 1   
       1 2 1 1 
       1 1 2 1 
       1 1 1 2
       4 0 0 0 ]

 b = [ 2 1 1
       1 2 1
       1 1 2 ]

then b can be created using a (b is wholly present in a). So output should be location of central element of b in a.

Here output is [3,3] else it should be [0,0].

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53 Solutions

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Last Solution submitted on Nov 16, 2025

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rifat on 16 Sep 2014

in test case 3, b is not available in a. I might be wrong.. Please Check

Jean-Marie Sainthillier on 16 Sep 2014

Not logic to ask a scalar (if no location), an array (if 1), and a cell (if 2). And why not add the example (difficult) in the tests ?

Vishal on 17 Sep 2014

@rifat : updated, thanks for info

Jan Orwat on 18 Sep 2014

Nice problem. Some solutions (using conv, filter2 etc.) doesn't check conditions properly. Adding a=2*ones(4); b=3*eye(3)+1; or a=0; b=0; or similar can improve the testsuite;

Jean-Marie Sainthillier on 18 Sep 2014

The solution in the example is [2 2;3 3].

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