I don't understand how this works with negative elements. For example if the input matrix is [0 -1;0 0] it is possible to obtain an arbitrarily low score by going [EastWest] sufficiently many times then EastSouth.
yeah... deleted the negative elements.. was foolish of me to think that way
The eye matrix is tricky - i must admit i cheated.. there is a of torugle with branching, i tried developing algorithm do "look up front" but failded...
I get 11 for test case 2.
May be you are considering the element at the bottom left corner. But, it is not necessary since diagonal movement is also allowed
OK, you're right about test case 2. I was wrong. But I get 6 for test case 1, not 7. The shortest path does not include upper right corner.
yeah, that is wrong.. corrected and thanks. too many mistake in a single problem
Spot the rectangle (Part 2)
Matrix with different incremental runs
Make a diamond
Implement a bubble sort technique and output the number of swaps required
Fermat's last theorem - again
Neither minima nor maxima
Elements with highest local average
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