Tanya, you like triangles.
Good one
Pythagoras theorem
These are interesting
a = sqrt(c^2-b^2);
good question
this isn't a calculation!
lol
what the
ez
test_1 a=sqrt(3) is longer than b=1
the good solution would be
a= min(sqrt(c^2 -b^2),b)
instead
regexp cheat
Kudos for finding this solution - it did indeed meet all the test cases, but wasn't quite what I had in mind! I will add a new test.
Sort a list of complex numbers based on far they are from the origin.
4327 Solvers
Sum all integers from 1 to 2^n
8414 Solvers
309 Solvers
Output any real number that is neither positive nor negative
316 Solvers
465 Solvers
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