Does r=uint64(308436464205151562) make sense? It seems like the argument to uint64 is a double precision number, so you have already lost the precision you are trying to gain by using uint64.
r=uint64(308436464205151562) outputs for uint64(r) 308436464205151562. However, r=308436464205151562 outputs for uint64(r) 308436464205151552. A very small loss in precision, but still a loss. The Challenge set has some numbers that use all the paint if full precision math was used. If residual paint was required as an output then full precision is needed. For solutions using p=p-2*r-1 the errors in r and p may cause issues.
Very novel input parameter adjustment to allow direct solution.
Nice bisecting search method and anonymous function for clean appearance.
Make a checkerboard matrix
Select every other element of a vector
Reindex a vector
Generate pi using logarithm
Adding and Subtracting UINT variables
Mastermind II: Solve in 8 or less
GJam 2017 Kickstart: Vote (Small)
Graceful Double Wheel Graph
GJam 2014 China Rd B: Sudoku Checker
GJam March 2016 IOW: Polynesiaglot Medium
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