Was able to reduce size a few times and finally got to this solution by borrowing tricks used by Grzegorz Knor and Dan.
Can you explain what the +'01'-'0' is doing? I don't see how i+'01'-'0'=[i,i+1].
'01 ' is a char vector of 2 positions: '0' ans '1'.
If you subtract '0' to it, it results a char vector with characters 0 and 1.
So '01'-'0' is the same as [0 1], but because of the '', it cost less operations.
Stuff the Board
Check if number exists in vector
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