cell2mat with 1* 1 cell array

Folks,

I have A{ii} which is a cell array 1*1 containing 18*9 matrix. I atttempt to convert to a matrix using B=cell2mat(A) but I get error stating

Cell contents reference from a non-cell array object.

I cannot change A{ii} to A(ii) is it violates

A(I) = B, the number of elements in B and
 I must be the same.

Any ideas? Regards B

[Matt Kindig]

What about

B = cell2mat(A{ii})

[bugatti79]

Hi Matt,

This is what i had, doesnt work....

Answer 1

[Azzi Abdelmalek]

Type

A
whos A

what did you get?

[Azzi Abdelmalek]

Try this

cell2mat([A{:}])

[bugatti79]

Hi Azzi,

No luck. The who function returns A as a 1*1 cell

[Azzi Abdelmalek]

What about

b=A{1}
whos b

[bugatti79]

Hi Azzi,

That seems to have worked in the for loop. Ie, I was able to create an 18*9 double matrix from a 1*1 cell containing 18*9 double using b=A{1} you advised. Can you explain what it is actually doing? Thanks in advanced B

[Azzi Abdelmalek]

Post your for loop

[bugatti79]

Actually, it doesnt work upon closer examination. b=A{1} means that it keeps the first matrix generated from the first loop and this carries through. I need to keep b as an index because in each loop b will be a different 18*9 matrix.

 for ii=1:size(nu_1,3);
  i=nu_1(:,:,ii);

A{ii}= i.*n.....
b=A{1}
c{ii}=b.*i %
end

      whos
      nu_1                18x9x6 double 
      A{ii}               1x1    cell
      n                   18*9   double
      b                   18x9   double 
      i                   18*9   double

[Azzi Abdelmalek]

I can't understand what this code is doing. To make your question clear, post a short sample of your data, then ask what you want

[Azzi Abdelmalek]

[bugatti79 commented]

Here is the code

nu = [25 25; 25 25]';
nu_1=nu;
nu_1(:,:,2)=50;
nu_1(:,:,3)=150;
nu_1(:,:,4)=300;
nu_1(:,:,5)=400;
nu_1(:,:,6)=450;

n=[ 100 100; 200 200]

for ii=1:size(nu_1,3)    
            i = nu_1(:,:,ii);

A(ii) = n.*i; 

B(ii) =c.*i.*n; % c a constant

C(ii)= i.*n.*B(ii).*C(ii)

end

If I run this code i get error..." A(I) = B, the number of elements in B and I must be the same. "

This is the problem that comes up as outlined in my first post on this thread... Hope this is clearer, thanks B

[Azzi Abdelmalek]

There are many errors in your code. you can't use A(ii)=matrix , you should use a cell array A{ii} with curly brackets. Another problem is this

 C(ii)= i.*n.*B(ii).*C(ii) % What is the value of C(ii) for ii=1?

Try to adapt this

clear
c=1;
nu = [25 25; 25 25]';
nu_1=nu;
nu_1(:,:,2)=50;
nu_1(:,:,3)=150;
nu_1(:,:,4)=300;
nu_1(:,:,5)=400;
nu_1(:,:,6)=450;
n=[ 100 100; 200 200]
C{1}=ones(size(nu));
for ii=1:size(nu_1,3)
  i = nu_1(:,:,ii);
  A{ii} = n.*i;
  B{ii} =c.*i.*n; % c a constant
  C{ii+1}= i.*n.*B{ii}.*C{ii}
end

[bugatti79]

My apologies,

C{ii}= i.*n.*B{ii}.*C{ii}

should read

D{ii}= i.*n.*B{ii}.*C{ii}

That should be workable now wit h your code right? Ie, just drop the +1?

[Azzi Abdelmalek]

Ok, but what is the value of C?

[bugatti79]

C needs to be a matrix not a single numeric value...

[Azzi Abdelmalek]

Then just use

D{ii}= i.*n.*B{ii}.*C