how rearrange data in a matrix?

I have a data as:

 data=[1 2 3 4 5 6 7 8];

I need a new data matrix (4 x 8),like this:

 new_data =[ 1 2 0 0 0 0 0 0
             0 0 3 4 0 0 0 0
             0 0 0 0 5 6 0 0
             0 0 0 0 0 0 7 8 ]

How to do it using a FOR loop ? Any help?

Answer 1

[Azzi Abdelmalek]

data=[1 2 3 4 5 6 7 8];
n=numel(data);
R=zeros(n/2,n);
R(:,1:2)=reshape(data,2,[])';
out=cell2mat(arrayfun(@(x) circshift(R(x+1,:),[ 0 2*x]),(0:3)','un',0))

%or

data=[1 2 3 4 5 6 7 8];
n=numel(data);
out=zeros(n/2,n);
out(sub2ind(size(out),repmat((1:n/2),2,1),reshape(1:n,2,[])))=data

%or

EDIT

n=numel(data);
a=[reshape(data,2,[]) ;zeros(n,n/2)];
a=a(:);
a(end-n+1:end)=[];
out=reshape(a,n,n/2)'

[Ved]

@Azzi: First two scripts worked perfectly.Thank you !

[Ved]

@Azzi:

Could you please explain the line which is using cell2mat() in your first code.

Answer 2

[Andrei Bobrov]

a = num2cell(reshape(data,1,2,[]),[1 2])
out = blkdiag(a{:});

or

out = kron(eye(4),[1 1])*diag(data);

or

out = reshape(permute(repmat(eye(4),[1,1,2]),[1 3 2]),4,[])*diag(data);

[Ved]

@Andrei:

Thank You ! but third one is giving an error:

 Error using repmat
Too many input arguments.

nevertheless other two options works perfectly.

[Andrei Bobrov]

corrected