Symbollically solving Ax=b

For example solve:

[a,b;c,d]*[x1;x2] = [b1;b2]

Matlab should return:

x1 = -(b*b2-d*b1)/(ad-bc) x2 = (a*b2 -c*b1)/(ad-bc)

thanks for your help,

Answer 1

[Shashank Prasanna]

It does.

>> syms a b c d x1 x2 b1 b2
>> x = solve([a,b;c,d]*[x1;x2]==[b1;b2])
>> x.x1
>> x.x2

You can start here:

http://www.mathworks.com/help/symbolic/solve.html

Check the documentation and post your attempt for quick, better response.