Problem with a loop in the hdl coder
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Hello,
I have written a matlab code and I try to produce a vhdl code by using the hdl coder. The problem is that the following error is appearing during the procedure of the code generation. "Found an unsupported unbounded loop structure. This loop may be user written or automatically generated due to the use of specific vector expressions or functions. For more information on unsupported loop structures, please refer to the documentation."
I have in the code a "while loop" and it seems that this error.Does anyone know why this error appears? As I know, the vhdl supports the "while loop".
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More Answers (2)
sin
on 24 Feb 2014
0 votes
i haven't used any loop still am getting the same error. can anyone help me with the solution?
thanks in advance!
1 Comment
DN
on 20 Jul 2016
Hi, have any of you had any joy on this. Can one use a For and While statement in a user defined function block in Simulink and still generate HDL code? Thanks
Tim McBrayer
on 21 Jul 2016
0 votes
For loops are supported, when they have fixed loop indices. While loops in general are not, as there is no way the compiler can determine how many loops will be executed. Keep in mind you are building hardware; no sizes can be left data-dependent, as your hardware cannot reconfigure itself at runtime based off of time-dependent input data.
This situation is the basis of the error message. HDL Coder must be able to statically determine, at compile time, how many times a loop will execute. In general a while loop does not execute a static number of times, so they are not supported. Hence, the "unbounded loop structure" message.
You can map while loops to for loops in many cases. The for loop should loop across the maximum range of iteration, while the body of the for loop has an if statement protecting the rest of the body so that the loop is in essence conditionally executed.
Finally: sometimes you can get an error referencing an unbounded loop when you have not written one explicitly in your code. This is most likely because you are calling a function, possibly even a built-in MATLAB function, that has such a loop in its underlying implementation.
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