How to create a struct

14 views (last 30 days)
Chao Zhang
Chao Zhang on 19 Jun 2021
Commented: Chao Zhang on 20 Jun 2021
There is a simple way to create a struct like the following picture, i.e ROCK = struct('ROCK0', value1, 'ROCK44', value2, 'ROCK50',value3, ....)
I was curious, is there any other ways to create a struct like the above, so i use for loop to do it, and the code is:
for m = 1 : size(rock_code,1)%Assign values to the initial cell
row_index = rock(:,col_ind_rk) == rock_code(m);%determine the row index according to the corresponding rock codes
sub_rock{m} = rock(row_index,:);
end
% Create string for each sub_rock
str_rock = cell(1,size(rock_code,1));%create cell to store strings
for kk = 1 : size(rock_code,1)
str_rock{kk} = sprintf('ROCK%d',rock_code(kk));
end
% Assign strings to each sub_rock
%create struct to store string and values
ROCK = struct;
for ii = 1 : size(rock_code,1)
ROCK = struct(str_rock{1,ii},sub_rock{1,ii});
end
But there is only the name and value of the last rock (i.e. ROCK53) in this structure, so, is there any way to achieve this struct like using for loop or other methods, thanks!
  2 Comments
Stephen23
Stephen23 on 19 Jun 2021
If you have any choice on the data design, then the best solution is to avoid forcing meta-data into fieldnames and simply use to basic arrays:
data = {1x13,2x13,2x13, .. etc}
rock = [ 0, 44, 50,51,52,53]
This makes processing the (meta-)data simpler and more efficient.
Chao Zhang
Chao Zhang on 20 Jun 2021
Thanks!

Sign in to comment.

Accepted Answer

Jonas
Jonas on 19 Jun 2021
Edited: Jonas on 19 Jun 2021
use
for ii = 1 : size(rock_code,1)
ROCK.(str_rock{ii}) = sub_rock{1,ii};
end
at the end if sub_rock cell entries are the values for the fields

More Answers (1)

Jan
Jan on 19 Jun 2021
str_rock = sprintfc('ROCK%d', rock_code); % Undocumented
ROCK = cell2struct(str_rock(:), sub_rock(:));

Categories

Find more on Structures in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!