Plotting content from structure

Hey, I am trying to plot values from a structure but somehow am getting Error using startswith.

Here is the code (examplified):

sges.location1 = 1;
sges.location2 = 2;
sges.location3 = 3,
sges.location4 = 4;
sges.location5 = 5;

sh.location1 = 4;
sh.location2 = 1;
sh.location3 = 2,
sh.location4 = 5;
sh.location5 = 3;

w1 = 0.6;
x = [1 2 3 4 5];
bar(x,sges,'FaceColor',[0.2 0.2 0.5])
ax = gca;
ax.YLabel.String = "Distance (km)"
title('Distance')
w2 = 0.5;
hold on
bar(x,sh,w2, 'FaceColor',[0 0.7 0.7])
grid on
legend({'sges', 'sh'}, 'Location', 'northwest')
labels = {'Loc1', 'Loc2', 'Loc3', 'Loc4', 'Loc5'};
set(gca, 'xtick', 1:5, 'XTickLabels', labels);

What am I doing wrong, am I missing something?

Answer 1

[VBBV]

sges.location1 = 1;
sges.location2 = 2;
sges.location3 = 3,

sges = struct with fields:
    location1: 1
    location2: 2
    location3: 3

sges.location4 = 4;
sges.location5 = 5;

sh.location1 = 4;
sh.location2 = 1;
sh.location3 = 2,

sh = struct with fields:
    location1: 4
    location2: 1
    location3: 2

sh.location4 = 5;
sh.location5 = 3;

w1 = 0.6;
x = [1 2 3 4 5];
C = struct2cell(sges)

C = 5×1 cell array
    {[1]}
    {[2]}
    {[3]}
    {[4]}
    {[5]}

cs = cell2mat(C)

cs = 5×1

1 2 3 4 5

H = struct2cell(sh)

H = 5×1 cell array
    {[4]}
    {[1]}
    {[2]}
    {[5]}
    {[3]}

hs = cell2mat(H)

hs = 5×1

4 1 2 5 3

bar(x,cs,'FaceColor',[0.2 0.2 0.5])
ax = gca;
ax.YLabel.String = "Distance (km)"

ax = 
  Axes with properties:

             XLim: [-0.2000 6.2000]
             YLim: [0 5]
           XScale: 'linear'
           YScale: 'linear'
    GridLineStyle: '-'
         Position: [0.1300 0.1100 0.7750 0.8150]
            Units: 'normalized'

  Show all properties

title('Distance')
w2 = 0.5;
hold on

bar(x,hs,w2, 'FaceColor',[0 0.7 0.7])
grid on
legend({'sges', 'sh'}, 'Location', 'northwest')
labels = {'Loc1', 'Loc2', 'Loc3', 'Loc4', 'Loc5'};
set(gca, 'xtick', 1:5, 'XTickLabels', labels);

Use struct2cell and cell2mat for converting the struct array to double

[Lukas Netzer]

Thank you very much!