is it possible to print 5decimal using disp commant

disp([x' u])

assume x and u are matrix

when i excute this, i get 0.9859.

i want to show with 5 decimal after point. 0.96875

[Mathieu NOE]

hello

you can use sprintf

%   Examples
%      sprintf('%0.5g',(1+sqrt(5))/2)       % 1.618
%      sprintf('%0.5g',1/eps)               % 4.5036e+15       
%      sprintf('%15.5f',1/eps)              % 4503599627370496.00000
%      sprintf('%d',round(pi))              % 3

[Rik]

@Mathieu NOE feel free to move your comment to the answer section, as I would say this is the answer.

@mehmet salihi you can either look at sprintf and fprintf or control the display of values in general with the format function.

Answer 1

[Image Analyst]

I'd use fprintf(), not sprintf(). fprintf() prints directly to the command window while sprintf() sends the result to a string. If you didn't specify a string, it will add "ans = " to the result, or the string variable name if you specified one, and enclose the number in single quote marks.

Compare these 3 different ways of doing it:

val = 0.96875123456789
fprintf('%.5f\n', val);    % Method 1 using fprintf
sprintf('%.5f', val)       % Method 2 using sprintf without assigning it to anything.
str = sprintf('%.5f', val) % method 3 using sprintf and assigning it to a variable called "str".

Results in command window:

0.96875

ans =

'0.96875'

str =

'0.96875'

[mehmet salihi]

i have matrix, not only one variable, how can i apply it to my matrix elements.

and i use the command below.

y=2:-0.05:0;

Told is matrix

disp([y' Told(:,find(abs(x-0.0) < 0.001)) Told(:,find(abs(x-0.2) < 0.001))...

Told(:,find(abs(x-0.4) < 0.001)) Told(:,find(abs(x-0.6) < 0.001))...

Told(:,find(abs(x-0.8) < 0.001)) Told(:,find(abs(x-1.0) < 0.001))])

[Rik]

Have you read the documentation for sprintf or fprintf?

Note that Matlab stores (and reads) arrays in column-major form, so you might need to transpose your matrix to get the expected result:

A=reshape(1:4,2,2);
disp(A)

     1     3
     2     4

fprintf('%d %d\n',A)

1 2
3 4

fprintf('%d %d\n',A.')

1 3
2 4