Urgent: How do I perform FFT on a time signal
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I have a vibration time signal am working on. I am finding it difficult to write the code to perform fft on it. Could anyone help with it please? The length of the signal is 40000 while the sampling frequency is 20000.
Additionally, how are the length of the signal and sampling frequency arrived at?
2 Comments
Youssef Khmou
on 26 Jul 2013
Jan
on 31 Jul 2013
While this question might be "urgent" for you, it is not "urgent" for all readers. Therefore it is recommended toavoid such pushing terms.
Answers (3)
dpb
on 26 Jul 2013
0 votes
doc fft
Sampling frequency is set by the hardware, time then determines the length.
Youssef Khmou
on 26 Jul 2013
Edited: Youssef Khmou
on 26 Jul 2013
hi, given your signal X,
Fs=2e+4;
Resolution=512;
Ts=1/Fs;
N=4e+4;
T=N*Ts;
Fx=abs(fft(X,Resolution));
Frequency=(0:Resolution-1)*Fs/Resolution;
figure, plot(Frequency(1:end/2),Fx(1:end/2)); % two sided to one side
Hi, just use the following code:
fs=20000; % sampling frequency
N=40000; % length of signal
dF=Fs/N;
f=-Fs/2:dF:Fs/2-dF; %remember nyquist frequency?
plot(f,abs(fftshift(fft(<your signal>)/N)));
Hope this helps!
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