fprintf 13 values in a 5x4 matrix without zeros.

I first change my data set from a matrix to vector using the reshape

A = reshape(OriginalA, numel(A),1)
B = reshape(OriginalB, numel(A),1)

then found the intersection

C=sextor(A,B); (13 by 1 vector)

turnC into a 5x4 matrix ncol=4 nrow=ceil(numel(C)/ncol); for i=1:nrows for i=1:ncol if j == nrows extran=nrows-round(numel(C)/ncol) for k=1:extran D(nrows,k)=C((i-1)*ncol+k); else D(i,j)=C(i-1)*ncol+j); end end end

Now I want to print it to a file where there are 4 or 8 columns because that was what a separate program wants.

d1, d2, d3, d4,
d5, d6, d7, d8,
d9, d10, d11, d12,
d13

Tried

    for i=1:nrow
          fprintf(fid,'%10i, %10i, %10i, %10,\n',D(i,1),D(i,2),D(i,3),D(i,4))
    end

it gives me the zeros though and I don't want them.

Answer 1

[Cedric]

The following might help (not tested):

 nCol = 4 ;
 Dt   = D.' ;
 nDt  = numel(Dt) ;
 for ii = 1 : nDt
    if Dt(ii) ~= 0,  fprintf(fid, '%10i', Dt(ii)) ;  end
    if ii < nDt,  fprintf(fid, ',') ;  end
    if ~mod(ii, nCol),  fprintf(fid, '\n') ;  end
 end

The initial transpose allows us to index Dt linearly for reading D along rows.

Answer 2

[Mark]

Perfect! I modified it a bit but thanks!