Unable to perform assignment because the left and right sides have a different number of element

hey

im new to matlab and i have problem i dont find how i can Increases the array size in a loop

i have tryed to use ones without succses

i will explain my code :

i have 6 game cube (1:6) and i have to throw all of them

i have to display all possible option which i did with sucsess i dont know if its the best option

but i also need to display all result that equal to 20 or bigger then 30 - here i need help

here is my code so far :

dbstop if error
cube=[1 2 3 4 5 6];

A=zeros(6^6,6); % number of the option
K=zeros(s,6);
L=zeros(s,6);
s=numel(A);
b20=0; % throwing cube ==20
b30=0; %;throwing cube >30
n=0; % counter
m=0; % counter

for i1=1:6
    for i2=1:6
        for i3=1:6
            for i4=1:6
                for i5=1:6
                    for i6=1:6
                        A=[i1 i2 i3 i4 i5 i6];
                        disp(A);
                        if (i1+i2+i3+i4+i5+i6)==20
                            b20=b20+1;
                            n=n+1;
                            K(n)=A;
                           
                        elseif (i1+i2+i3+i4+i5+i6)>30
                            b30=b30+1;
                            m=m+1;
                           L(n)=A;
                          
                        end
                    end
                end
            end
        end
    end
end

i will appriciate any help and improvment to my code

Answer 1

[Jan]

K(n, :) = A;
%    ^

L(n, :) = A;
%    ^

The vector A can be assigne to the vector of the array K and L only. K(n) is a scalar, the same as K(n, 1).

Another problem:

K=zeros(s,6);   % s is used
L=zeros(s,6);
s=numel(A);     % but defined later only.
% But you do not need numal(A) outputs, but size(A, 1) only

Pre-allocating A by "A=zeros(6^6,6);" is not needed, if you overwrite it in the code:

A=[i1 i2 i3 i4 i5 i6];

The variable n and b20 as well as m and b30 have the same values. To you can omit n and m, or b20 and b30.

The variable cube is not used anywhere. So you can omit the line "cube=[1 2 3 4 5 6];"

[the cyclist]

This is a very helpful and complete answer.

Just to be finicky, though ... K(n) is not the same as K(n,1), in general.

[Jan]

@the cyclist: Thanks.

Correct: If K is a row vector, K(n) is working fine and K(n,1) is failing. For arrays, which are not row vectors, both is the same - or do I oversee a detail?

[the cyclist]

I was thinking of an array where n is larger than size(K,1), for example:

n = 5;
K = rand(3,6);
K(n) % Correct linear indexing

ans = 0.5661

K(n,1) % Error with subscript indexing

Index in position 1 exceeds array bounds (must not exceed 3).

[Jan]

Yes, now I understand your comment. Thanks for the explanation. Sometimes experiences block my view on trivial bugs, because I would avoid them intuitively.

Answer 2

[the cyclist]

You need to use

K(n,:)=A;

and

L(n,:)=A;

to assign the row vector A to a row of K or L.

K(n) is a single element, using linear indexing.