finding distance of distinct value

Hi, suppose I have a matrix as follows:

I =

     1     1     5     1     1     1     8
     1     1     1     1     1     1     1
     1     1     1     1     1     1     1
     1     1     1     2     1     1     1
     1     1     1     1     1     6     1
     1     1     3     1     1     1     1

I(3,4) is 1 . I need to know the distance of this one from the distinct value of this matrix.i.e distances of 2,3,5,6,8. How to do this easily? and also need the matrix position of that value.Thanks in advance.

Answer 1

[Andrei Bobrov]

variant

o34 = zeros(size(I));
o34(3,4)=1;
o34d = bwdist(o34);
distato34 = [I(I~=1) o34d(I~=1)]

more variant

o = [3 4];
dC = arrayfun(@(x)(cumsum(ones(size(I)),x)-o(x)).^2,1:2,'un',0);
d = sqrt(dC{1} + dC{2});
l = I~=1;
out = [I(l) d(l)]

more more variant

[Hi Hj] = find(I~=1);
out = [I(I~=1) sqrt(sum(bsxfun(@minus,[Hi Hj],[3 4]).^2,2))]