How can I layer coordinate matrixes into a cell of vectors? (iteration over matrices)

I have 3 matrices of coordinates, say:

x=[1,2;1,2] , y=[1,1;2,2] , z=[5,6;7,8]

I want to somehow combine them to get a cell that holds at each spot a 1X3 double of the vector at that spot, as in:

A= [1,1,5]    [2,1,6] ; 

   [1,2,7]    [2,2,8]

the following doesn't work:
A(:,:)=[x(:,:),y(:,:),z(:,:)]

I tried layering the matrixes:
temp=cat(3,x,y,z)
a={permute(temp(1,2,:),[2,3,1])}
R=cell(2,2)
R(1,1)=a

but this will only give me a single vector, and i want to do this at every index over a large matrix (without using loops as it becomes very slow)

(I want to be able to keep the vectors 'next' to their original neighbours, so please don't tell me to 'spread' the data into a 3*n matrix as then I would lose that information)

anyone know a good way to iterate over the matrices? thanks in advance!

Answer 1

[Azzi Abdelmalek]

x=[1,2;1,2];
y=[1,1;2,2]; 
z=[5,6;7,8];
A=arrayfun(@(a,b,c) [a b c],x,y,z,'un',0)

[gail]

thank you!!!!