Adjusting size of matrix when converting base 10 to binary

I'm looking to convert a number (0-255) into binary and then put that into a 1x8 matrix returning 1 and 0's. The issue I'm having is fitting the vectors together since a number like 30 gives [1 1 1 1 0] rather than [0 0 0 1 1 1 1 0]. I'd prefer not to manually add in the first rows each time I get to the next 2^n.

Any help is appreciated.

NumBin = num2str(dec2bin(30)) - '0';
    %Returns 1 1 1 1 0
NumBin = num2str(dec2bin(255)) - '0';
    %Returns 1 1 1 1 1 1 1 1

    %Looking for:
%   0 0 0 1 1 1 1 0
%   1 1 1 1 1 1 1 1

Answer 1

[James Tursa]

Specify the number of binary digits to use. E.g.,

dec2bin(30,8)

[Samuel Brewton]

Works perfectly! Thank you.