[B,TF] = rmoutliers(A,method) on older MATLAB version (2016) ?

my file size is [12*3]; i am writing without inbuilt function code and i am struct at nonoutlier

in this figure shows my isoutlier ''B'' output ;in that if 1 is present in any one [X,or Y, or Z] of the column remove entire row of [X,Y,Z]

and i was struct at my nonoutliers output matrix is [32*1]

can you help me to get nonoutlier matrix size [8*3]

i need your help,thank you

S = readtable('object.xlsx');
X = S.X;
Y = S.Y;
Z = S.Z;
position = [X Y Z];
TF=median(position);
M_d=mad(position,1);
c=-1/(sqrt(2)*erfcinv(3/2));
smad=c*M_d;
tsmad=3*smad
B=(abs(position-TF)>=tsmad);
outlier = position(B);
nonoutliers = position(~B)

Answer 1

[Cris LaPierre]

It is 32x1 because you are using linear indexing. This happens when you index an array with a single index (even though that index may be an array).

3 columns x 12 rows = 36 elements

36 - 4 outliers = 32

If you want an array back, you must supply row and column indeces. Try something like this for the final line of code:

nonoutliers = position(all(~B,2),:)

[swathi]

thank you sir