Storing values in a matrix from 2 for loops

First I'll post my code then explain

P=100;
E=1.5*10^6;
b=3.375;
d=1.5;
I=(1/12)*b*d^3;
L=20;
a=10;

for x1=0:.2:a
    y1=((-P*x1)/6*E*I)*(1-(a/L))*((2*a*L)-(a^2)-(x1^2));
end
for x2=a+.2:.2:L
    y2=((-P*a)/(6*E*I))*(1-(x2/L))*((2*x2*L)-(a^2)-(x2^2)); 
end

Now with this code i get 51 values from y1 and 50 values from y2. I need these to be stored in a 1 x 101 matrix. How can this be done?

Answer 1

[Paulo Silva]

P=100;
E=1.5*10^6;
b=3.375;
d=1.5;
I=(1/12)*b*d^3;
L=20;
a=10;
y11=[];
y21=[];
for x1=0:.2:a
    y1=((-P*x1)/6*E*I)*(1-(a/L))*((2*a*L)-(a^2)-(x1^2));
    y11=[y11 y1];
end
for x2=a+.2:.2:L
    y2=((-P*a)/(6*E*I))*(1-(x2/L))*((2*x2*L)-(a^2)-(x2^2)); 
    y21=[y21 y2];
end

yf=[y11 y21]

%yf is your response, 1x101 it's a vector not a matrix

[Brian]

thanks! works great

Answer 2

[Andrei Bobrov]

variant

P=100;
E=1.5*10^6;
b=3.375;
d=1.5;
I=(1/12)*b*d^3;
L=20;
a=10;
x1=0:.2:a;
x2=a+.2:.2:L;
f=@(X,Y,Z)((-P*X)/(6*E*I)).*(1-(Y/L)).*((2*Y*L)-(a^2)-(Z.^2));
count = [f([x1,a,x1), f(a,x2,x2)]