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This simple code note working, HELP

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%this works well upto t==0.7, but not after 0.8
%give me an answer for this, not links
t=0;
for n=1:10
t=t+0.1;
disp(t)
if t==0.8
disp('if')
else
disp('else')
end
end

Accepted Answer

Ameer Hamza
Ameer Hamza on 13 Jun 2020
Edited: Ameer Hamza on 13 Jun 2020
Direct comparison using == of floating-point number does not give the correct result. You need to allow some level of tolerance. Try this
t=0;
for n=1:10
t=t+0.1;
disp(t);
if abs(t-0.8) < 1e-6
disp('if')
else
disp('else')
end
end
  3 Comments
Ameer Hamza
Ameer Hamza on 13 Jun 2020
yes, that will work as well, but it is good to use the tolerance method. Otherwise, you will need to do rounding every time you do some mathematical operation on the variable.
Poojitha Ariyathilaka
Poojitha Ariyathilaka on 13 Jun 2020
Yes, tolerance method is much quicker.

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