Blank figures appearing for plots
Show older comments
I've create an adaptive time-stepping function and I'm trying to plot the graphs but it is just creating blank figures.
Here is my function:
function [tvec,yvec,dtvec]=adaptive_euler(f,ytrue,y0,t0,dt0,dtmin,dtmax,tmax,alpha,beta,gamma,TOL)
y=zeros(10^5,1);
y(1)=y0;
dt=zeros(10^5,1);
t=zeros(10^5,1);
dt(1)=dt0;
yt=y0;
yt1=y0;
t(1)=t0;
n=1;
while (t(n)<tmax && dt(n)<dtmax && dt(n)>dtmin)
yt=yt+dt(n)*f(t(n),yt);
yt1=yt1+(dt(n)/2)*f(t(n),yt1);
yt2=yt1+(dt(n)/2)*f(t(n),yt1);
Et2=(yt2-yt)/(dt(n));
c=TOL/norm(Et2);
if norm(Et2) < TOL
y(n)=yt2;
t(n+1)=t(n)+dt(n);
n=n+1;
end
dt(n) = min(max(alpha*c*dt(n-1),gamma*dt(n-1)),beta*dt(n-1));
end
tvec=zeros(n,1);
yvec=zeros(n,1);
dtvec=zeros(n,1);
for i=1:n
tvec(i)=t(i);
yvec(i)=y(i);
dtvec(i)=dt(i);
end
yreal=zeros(n,1);
error=zeros(n,1);
for i=1:n
yreal(i)=ytrue(tvec(i));
error(i)=abs(yvec(i)-yreal(i));
end
T1=table(n,error(n));
figure(1)
plot(tvec,yvec,'.',tvec,yreal,'--');
legend('Approx:','True:');
title('Graph of the Adaptive Eulers Method approximation of dy/dx=-exp(2*t)*y^2 against real values');
figure(2)
plot(tvec,dtvec)
title('Graph of the change in dt over t');
end
And here is the script:
f=@(t,y)-exp(2*t)*y^2;
t0=0;
y0=2;
dt0=0001;
dtmin=10^-10;
dtmax=0.5;
tmax=10;
alpha=0.84;
beta=4;
gamma=0.1;
TOL=0.1;
ytrue=@(t)2*exp(-2*t);
[tvec,yvec,dtvec]=adaptive_euler(f,ytrue,y0,t0,dt0,dtmin,dtmax,tmax,alpha,beta,gamma,TOL)
Thank you!
4 Comments
Adam
on 10 Mar 2020
Simplest option - stick a breakpoint on the plotting line and look at what is in tvec and yvec or dtvec or whichever plot is causing the problem. It may be obvious then what the problem is.
As an aside, don't use a for loop like this:
tvec=zeros(n,1);
yvec=zeros(n,1);
dtvec=zeros(n,1);
for i=1:n
tvec(i)=t(i);
yvec(i)=y(i);
dtvec(i)=dt(i);
end
It is a much slower and more convoluted version of simply
tvec = t;
yvec = y;
dtvec = dt;
And then once you've simplified it to that one would have to ask why do it at all? Why not just use t, y and dt instead of the new vectors that are an exact copy?
Phoebe Tyson
on 10 Mar 2020
Adam
on 10 Mar 2020
But you set them up as vectors of length n and then you copy from 1 to n from another vector into these.
Phoebe Tyson
on 10 Mar 2020
Answers (1)
Image Analyst
on 10 Mar 2020
You never enter the while loop
while (t(n)<tmax && dt(n)<dtmax && dt(n)>dtmin)
because dt(1) is 1 and dtmax is 0.5. Pass in a different dtmax.
2 Comments
Phoebe Tyson
on 10 Mar 2020
Image Analyst
on 10 Mar 2020
1 is also not less than 0.001, so that won't enter the loop either. So what did you pass in?
In the meantime, see the FAQ: Subscript_indices_must_either_be_real_positive_integers_or_logicals.
Categories
Find more on Graphics Objects in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!