Why isn't my graph plotting correctly?
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Hi, I think I must be being dense, I am attempting to plot
in Matlab, but I am getting a plot that is very wrong.
km=linspace(0,10,100);
y=tan(km)+tanh(km);
plot(km,y,'color','red','LineWidth',1.5);
xlabel('$k_m$','Interpreter','latex');
ylabel('$f(x)$','Interpreter','latex');
title('Graph of $f(x)=tan(k_m)+tanh(k_m)$','Interpreter','latex')

Please could someone explain what I have done wrong to obtain this:
Cheers
3 Comments
Adam
on 12 Nov 2019
What is the graph you are expecting?
Monkeyman
on 12 Nov 2019
Adam
on 12 Nov 2019
I suspect the difference is simply that it is joining asymptotes together in the plot. If you explicitly insert NaNs in your data at the points of the asymptotes (or basically between the points either side of one) this should get rid of that, I think.
Answers (1)
Star Strider
on 12 Nov 2019
Set the peaks values to NaN and they will not plot:
km=linspace(0,10,1000);
y=tan(km)+tanh(km);
[pks,locs] = findpeaks(y); % Locate Peaks Peaks
y(locs) = NaN; % Set Peaks To ‘NaN’
plot(km,y,'color','red','LineWidth',1.5);
xlabel('$k_m$','Interpreter','latex');
ylabel('$f(x)$','Interpreter','latex');
title('Graph of $f(x)=tan(k_m)+tanh(k_m)$','Interpreter','latex')
ylim([-6 +6])
grid
2 Comments
Monkeyman
on 12 Nov 2019
Star Strider
on 12 Nov 2019
To the best of my knowledge, findpeaks will not work on function handles. If you want to use fzero to find the zero-crossings, this is an appropriate approach:
km = linspace(0,10,100);
y = tan(km)+tanh(km);
[pks,locs] = findpeaks(y); % Locate Peaks Peaks
y(locs) = NaN; % Set Peaks To ‘NaN’
f=@(km) tan(km)+tanh(km);
midpt = fix(mean(diff(locs))/2);
for k = 1:numel(locs)
idx = min([numel(km) locs(k)+midpt]); % Prevents Indexing Beyond ‘km’ Length
zro(k) = fzero(f, km(idx));
end
It returns the zero-crossings in the ‘zro’ vector.
Experiment to get the result you want.
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