How to create an array and fill it by these values using loop ?

how to creating a 480*1 single array (not datetime) and fill it this way:

1982-01-01

1982-02-01

1982-03-01

1982-03-01

1982-04-01

.

.

.

2015-12-01

(it does not matter if even there is only text)

I don't know how to do it, please help in this issue. thank you all

Answer 1

[Fabio Freschi]

% intialization and preallocation
k = 1;
date = strings(480,1);  % string array
 
for i = 1982:2015
    for j = 1:12
        % concat string
        date(k) = strcat(num2str(i),'-',num2str(j,'%02d'),'-01');
        % display strings
        fprintf('%s\n',date(k));       
        % increment
        k = k+1;
    end
end

[Stephen23]

Rather than this complex group of commands:

strcat(num2str(i),'-',num2str(j,'%02d'),'-01')

Simpler to use one sprintf call:

sprintf('%d-%02d-01',i,j)

Answer 2

[Adam Danz]

Why use a loop?

ds = datestr(datenum(1982, 01, 01) + cumsum([0;ones(479,1)]),'yyyy-mm-dd'); 

Result: (first 5 rows)

ds(1:5,:)
ans =

  5×10 char array

    '1982-01-01'
    '1982-01-02'
    '1982-01-03'
    '1982-01-04'
    '1982-01-05'

[Addendum]

On second thought, this is simpler and avoids cumsum()

ds2 = datestr(datenum(1982, 01, 01) + (0:479).','yyyy-mm-dd'); 

[Stephen23]

+1 effective use of MATLAB.