Assembling Element Matrices in Finite Element Method Problem
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I should start with mentioning I am die hard newbie who has term project about a hydraulic problem which I have to solve with Matlab.
So far I've calculted KK{i} 3x3 matrices but now I have to put them in a element matrices to proceed forward with my solution.
The matrix should look like this with the help of KK{i} matrices;

( The KK{1} and KK{2} in the solution manual )
( As you can see they have the placements in overall matrix that we're planning to achieve. The 6 1 2 that I've crossed comes from the ElemX, ElemY and ElemZ)

( For those helpful people here's the interpolation scheme)
The Overall Matrix that we're planning to achieve looks like;

I've found some helpful formulations but I am unable to fit them to my code.
So sorry if it is a lame or too chaotic to understand..
Don't mind the Turkish explainations in the code.
echo off all
clc
nodeX = [0,5,9.17,12,0,5,9.17,12,0,5,8,9.17,12]; % noktalarin x koordinatlari
nodeY = [8,8,8,8,4,4,5.5,5.5,0,0,0,2.83,4]; % noktalarin y koordinatlari
elemX = [5,6,6,7,7,7,5,9,10,11,6,7,7]; % i icin olusan ucgenlerin global nokta karsiliklari
elemY = [1,1,2,2,3,4,6,6,6,6,7,12,8]; % j icin
elemZ = [6,2,7,3,4,8,9,10,11,12,12,13,13]; % k icin
varTable = [];
fprintf("e xi\txj\txk\tyi\tyj\tyk\tck\tci\tcj\tbi\tbj\tbk\tA\n"); % tablo basligini formatla
for i = 1:length(elemX)
% sirasiyla elemanlari okutuyoruz
currElemX = elemX(i);
currElemY = elemY(i);
currElemZ = elemZ(i);
% i ye karsilik gelen global noktalarin koordinat karsiliklari
% bulunuyor
xi = nodeX(elemX(i));
xj = nodeX(elemY(i));
xk = nodeX(elemZ(i));
yi = nodeY(elemX(i));
yj = nodeY(elemY(i));
yk = nodeY(elemZ(i));
% gerekli hesaplama yapiliyor
ck = xj - xi;
ci = xk - xj;
cj = xi - xk;
bi = yj - yk;
bj = yk - yi;
bk = yi - yj;
% alan hesabi
A = abs(0.5 * (xi * yj + xj * yk + xk * yi - xi * yk - xj * yi - xk * yj));
%dongunun disinda kullanmak icin bulunan degerleri sakla
varTable = [varTable ; ck,ci,cj,bi,bj,bk,A];
% ekrana uygun formatla yazdiriliyor
fprintf("%d %.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.4f\t\n",i,xi,xj,xk,yi,yj,yk,ck,ci,cj,bi,bj,bk,A);
end
Kcal= array2table(varTable, 'Variablenames',{'ck','ci','cj','bi','bj','bk','A'}) %K 3x3 matris hesabi icin tablo
%tablodaki degerleri disari cekiyorum sutunlari ayri olarak
%A='Tablename'.'variablename' komutu ile
%n sembolu sondaki sadece karisiklik onlemek amacli
cint=Kcal.ci;
cjnt=Kcal.cj;
cknt=Kcal.ck;
bint=Kcal.bi;
bjnt=Kcal.bj;
bknt=Kcal.bk;
Ant=Kcal.A;
%Transpoze ediyoruz satira cevirmek icin sutun matrisini
bin=bint.';
bjn=bjnt.';
bkn=bknt.';
cin=cint.';
cjn=cjnt.';
ckn=cknt.';
An=Ant.';
%Yazdiracagimiz icin basliklar \t ile tab bosluk biraktirliyor \n ile yeni
%satir yazdiriliyor.
fprintf("e\t K11\tK12\tK13\tK21\tK22\tK23\tK31\tK32\tK33\n"); % tablo basligini formatla
%Degiskenler icin bos matris
varTable2 = [];
for i=1:height(Kcal) % Kcal sutun olarak dizildigi icin height kullandik.
currcin=cin(i);
currcjn=cjn(i);
currckn=ckn(i);
currbin=bin(i);
currbjn=bjn(i);
currbkn=bkn(i);
currAn=An(i);
cinn=cin(i);
cjnn=cjn(i);
cknn=ckn(i);
binn=bin(i);
bjnn=bjn(i);
bknn=bkn(i);
Ann=An(i);
% K Row x Column olarak isimlendirir isek, 3x3 matrisin degerleri
K11=(1/(4 * Ann)) * ( binn^2 + cinn^2);
K12=(1/(4 * Ann)) * ((binn * bjnn) + (cinn * cjnn));
K13=(1/(4 * Ann)) * ((binn * bknn) + (cinn * cknn));
K21=(1/(4 * Ann)) * ((binn * bjnn) + (cinn * cjnn));
K22=(1/(4 * Ann)) * ((bjnn)^2 + (cjnn)^2);
K23=(1/(4 * Ann)) * ((bjnn * bknn) + (cjnn * cknn));
K31=(1/(4 * Ann)) * ((binn * bknn) + (cinn * cknn));
K32=(1/(4 * Ann)) * ((bjnn * bknn) + (cjnn * cknn));
K33=(1/(4 * Ann)) * ((bknn)^2 + (cknn)^2);
varTable2 = [varTable2 ; K11, K12,K13, K21, K22, K23, K31, K32, K33]; %Degiskenleri tabloya aliyoruz
fprintf("%d\t%.4f\t%.4f\t%.4f\t%.4f\t%.4f\t%.4f\t%.4f\t%.4f\t%.4f\t\n",i,K11,K12,K13,K21,K22,K23,K31,K32,K33);
end
Kcal2= array2table(varTable2, 'Variablenames',{'K11','K12','K13','K21','K22','K23','K31', 'K32', 'K33'}) %K 3x3 matris hesabi icin tablo2
%K matrislerini olusturmak icin verilerimiz hazir.
%Siradaki islem bu verileri 3x3 Matrislere yerlestirmek.
% 1.SIRA: K1 K2 K3 VERILERINI AYRI AYRI CEKMEK
%%%%%%%%%%%%%%%%%% BURADA KOPUYORUM %%%%%%%%%%%%%%%%%%%%%%
for i=1:9
%GEREKSIZ%
varK = [1:1:i]; %1 den i ye kadar rakamlardan olusan satir matrisi yazdirdik
%GEREKSIZ%
K{i}=varTable2(i,:); %1x9 matrisleri K{1} K{2} olarak ayirir row matrisi olarak
end
for i=1:9
KK{i}=reshape(K{i},[3,3]); %% KK{i} adiyla 3x3 matrislerimizi elde ettik.
%%%%%%% cell olarak kaydetmistik bunlari double yapmamiz lazim
%%%% cell ve double arasi fark nedir???
end
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