if NaN then...
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Clarisha Nijman
on 2 Jan 2019
Commented: Clarisha Nijman
on 4 Jan 2019
Dear all,
I have a function that returns me a PMatrix. But sometimes that matrix is full with nan's. The cause is known, but the best solution I found is to allow the function to compute such kind of "nan" matrices and to replace that "NaN matrix in the end by the identity matrix.
This is my actual code that works fine, uptill now.
Som=sum(sum(PMatrix));
Som(isnan(Som))=1;
if Som==1
PMatrix=eye(k,k);
end
I find this code clumsy and would prefer a more straight forward code saying:
if sum(sum(PMatrix))=NaN
PMatrix=eye(k,k)
end
But I can't figure out how to compose such a straight forward code. Does anyone has a suggestion for me?
Thank you in advance.
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Accepted Answer
Steven Lord
on 2 Jan 2019
Which release are you using? For release R2018b or later:
if any(isnan(PMatrix), 'all')
end
For release R2018a or earlier:
if any(isnan(Pmatrix(:)))
end
More Answers (1)
GT
on 2 Jan 2019
Edited: per isakson
on 3 Jan 2019
Have you tried using the function isnan?
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