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How to generate a random number of n bits length?

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Mohsin Shah
Mohsin Shah on 6 Sep 2018
Commented: John D'Errico on 18 Nov 2020
Let's say a function takes input n as the bit length and outputs a random number. For example, for n = 4, the output range is [0 - 15] which also includes the range for n = 3 i.e. [0 - 7]. The function should generate the number in the range [8 - 15] and not in the range [0 - 15]. How to do this and how to generalize it for any n?
  3 Comments
KALYAN ACHARJYA
KALYAN ACHARJYA on 6 Sep 2018
@Mohsin Check my answer, as per your requirement? If any modification required, let me know.

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Accepted Answer

Guillaume
Guillaume on 6 Sep 2018
For n = 4 it should generate a number in the range [8-15]
If I understand correctly, you want a 4 bit random number with the MSB always set to 1. That sounds like a strange requirement, probably not thought properly, but this is simply equivalent to generating a 3 bit random number and tacking 1 as the MSB. The generic version of that (generating a n-1 bit number + MSB of 1) is:
n = 4
number = randi([1, 2^(n-1)]) + 2^(n-1) - 1
  3 Comments
John D'Errico
John D'Errico on 18 Nov 2020
@ANz Eisenheim - please don't revive dead questions with a new question. If you have a new question, then ask it separately.
Regardless, what is the problem? Generate random bits as a vector. rand can do it. randi can do it. As long as the sequence is of a length that is a multiple of 4, you are done. So WTP?

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More Answers (1)

KALYAN ACHARJYA
KALYAN ACHARJYA on 6 Sep 2018
Edited: KALYAN ACHARJYA on 6 Sep 2018
function bit_result=rand_bits(n)
result=randi([2^(n-1), 2^n]);
bit_result=de2bi(result,n)
end
  3 Comments
Mohsin Shah
Mohsin Shah on 6 Sep 2018
I appreciate your efforts but the edited function still doesn't work. Check the answer of Guillaume which worked for me.

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