solving rlc circuit using ode45

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sami alzeq
sami alzeq on 8 Aug 2018
Commented: sami alzeq on 9 Aug 2018
i have homework to solve rlc circuit using ode45 i tried this code and the question is how to plot Vl1 anyone can help me please and if there is any mistake in this code
function RLC=homework(t,x)
R1=20;R2=30;L1=4*10^-3;L2=2*10^-3;C=0.004;u=100;
RLC(1)=(R1/L1)*(x(1))+(1/L1)*(x(2))-(1/L1)*u;
RLC(2)=-(R2/L2)*(x(2))+(1/L2)*(x(3));
RLC(3)=(-1/C)*(x(1))-(1/C)*(x(2));
RLC=RLC';
[t,x]=ode45('homework',[0 10],[2;2;2]);
  2 Comments
James Tursa
James Tursa on 8 Aug 2018
You are missing a minus sign on the first rhs term on the x1dot line:
RLC(1) = -(R1/L1)*(x(1)) + (1/L1)*(x(2)) - (1/L1)*u;

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Accepted Answer

Aquatris
Aquatris on 9 Aug 2018
If you were to use the code;
[t,y] = ode45(@homework,t,[0 0 0]');
the y here is your i1, i2, and vc.
From here you should know how to get desired Voltages (Kirschof law etc.).
The subplot command will be used as;
subplot(4,1,1),plot(t,Vl1) % "subplot(4,1,2)" means there will be
subplot(4,1,2),plot(t,Vr2) % 4 rows and 1 column in total for
subplot(4,1,3),plot(t,Vr1) % the plots and this one is the 2nd
subplot(4,1,4),plot(t,Vc) % plot
Similar thing for the currents.
In part 4, you just need to replace u in the function with the sine wave.
Is there any particular question you have other than these?

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