How to compare two vectors with different dimensions to get logical array?

Hello, I have two vectors with different dimensions. To make it simple,lets say A=[775.4; 770.2; 690;...] is n by 1 and B is m by 2: for example, B(1,:)=775.446,774.706. Basically, I want this: if A(i,1)<=B(i,1) & A(i,1)>=B(i,2) is true,then do sth. i tried to use for statement such as for i=size(A),obviously, theres problem because of the two dimensions. If anybody knows how to solve this problem, please let me know. Thanks.

[Sean de Wolski]

And you want to do this for each value of A, wotjh each value of B?

[Sean de Wolski]

Please provide the expected result for your simple example.

[Lei]

Hi Sean,

Thanks for your help!

Yes,I want to do this for each value of A.

What I want is: if each of the value of A is in the range of row of B ( because each row of my B has two values). Then I do sth else. The reason i did not put the other code is here is that they look complicated.

In my case, my A is 700 by 1 and my B is 30 by 2.

Any of your help will be appreciated!

Answer 1

[Jan]

A = rand(10, 1);
B = rand(20, 2);

n = min(size(A, 1), size(B, 1));
R = A(1:n) <= B(1:n, 1) & A(1:n) >= B(1:n, 2);
for i = 1:n
  if R(i)
    ...
  end
end

Or:

n = min(size(A, 1), size(B, 1));
for i = 1:n
  if A(i) <= B(i, 1) & A(i) >= B(i, 2)
    ...
  end
end

[Lei]

Hi Jan,

Thanks for your help!

It works well!

[Lei]

Hi Jan,

What if the size of A is larger than the size of B?

What can I do to solve this problem? Actually,I did not notice this until i tried to run my own code.