Passing function handle to another function and assigning varying number of input arguments to it
1 view (last 30 days)
Show older comments
Hi,
I am trying to write a code in which I need to pass a handle function to another function, let say
function b=myfun1(a)
b=2*a;
end
function b=myfun2(handle_f,a)
b=a*handle_f(a)
end
result=myfun2(@(aa)myfun1(aa),a);
Well, this works perfectly fine. Now let say that I want to decide to vary the number of and type of arguments of myfun1 or use completely different function. How should I write myfun2 to be able to work with any type of function with different number of input arguments and of course same output type?
0 Comments
Answers (1)
Andrei Bobrov
on 20 Apr 2012
eg
function b=myfun2(handle_f,varargin)
a = varargin{1};
b=a.*handle_f(varargin{:})
end
on Hossein's comment
myfun2(@(x)myfun3(x,y),a); %here y is defined
myfun2(@(y)myfun3(x,y),a); %here x is defined
myfun2(@(x,y)myfun3(x,y),a,y);
myfun2(@(y,x)myfun3(x,y),a,x);
2 Comments
Andrei Bobrov
on 21 Apr 2012
myfun2(@(x)myfun3(x,y),a); %here y is defined
or
myfun2(@(y)myfun3(x,y),a); %here x is defined
See Also
Categories
Find more on Argument Definitions in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!