Removing components of a matrix without turning it into a vector
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Hello I'm trying to remove the Inf values from my matrix Z without turning it into a vector. I have an idea of how to do it using loops, and I know Z(1,:)=[] + Z(:,4)=[] will work as I want it to but I wanted to see if there's a quicker way because it seems like this should be a trivial thing for MATLAB. Z is actually a sample matrix, the matrix I am working with is larger and within a function, so the Inf locations will always be different.
Thanks!
Z =
Inf Inf Inf Inf
4 6 13 Inf
10 12 19 Inf
11 18 25 Inf
>> Z(Z==Inf)=[]
Z =
4 10 11 6 12 18 13 19 25
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Accepted Answer
Andrei Bobrov
on 3 Oct 2017
Edited: Andrei Bobrov
on 3 Oct 2017
ii = isinf(Z);
out = Z(~all(ii,2),~all(ii));
or
ii = ~isinf(Z);
out = reshape(Z(ii),max(sum(ii)),[]);
More Answers (1)
KSSV
on 3 Oct 2017
doc isinf . You can pick the values from Z which are not inf, instead of removing them.
iwant = Z(~isinf(Z))
6 Comments
KSSV
on 3 Oct 2017
Z = [ Inf Inf Inf Inf
4 6 13 Inf
10 12 19 Inf
11 18 25 Inf]
%%Remove _inf_ along rows
Z(any(isinf(Z(:,1))),:) =[] ;
%%Remove _inf_ along cols
Z = Z(:,~all(isinf(Z)));
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